document.write( "Question 935055: The length of a rectangle is 7yds
\n" ); document.write( "less than three times the width, and the area of the rectangle is 66yds^2
\n" ); document.write( " . Find the dimensions of the rectangle.
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Algebra.Com's Answer #568177 by MathTherapy(10552)\"\" \"About 
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The length of a rectangle is 7yds
\n" ); document.write( "less than three times the width, and the area of the rectangle is 66yds^2. Find the dimensions of the rectangle.
\n" ); document.write( "

\n" ); document.write( "Let width be W
\n" ); document.write( "Then length = 3W - 7
\n" ); document.write( "We then get: W(3W - 7) = 66
\n" ); document.write( "\"3W%5E2+-+7W+-+66+=+0\"
\n" ); document.write( "(W - 6)(3W + 11) = 0
\n" ); document.write( "W - 6 = 0 OR 3W + 11 = 0
\n" ); document.write( "W, or width = \"highlight_green%286%29\" yds OR 3W = - 11(ignore)
\n" ); document.write( "Length: 3(6) - 7, or 18 - 7, or \"highlight_green%2811%29\" yds \n" ); document.write( "
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