document.write( "Question 934641: the dollare price for a barrel of oil sold at a certain oil refinery tends to follow the demand equation below, where x is the number of barrels of oil on hand( in millions)
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document.write( "A) how much should be charged for a barrel of oil on hand
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document.write( "B) what quantity x will maximize revenue? what is the maximum revenue
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document.write( "C) what prcies should be charged in oreder to maximize revenue\r
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document.write( "P=-1/5x+140 \n" );
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Algebra.Com's Answer #568175 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the dollare price for a barrel of oil sold at a certain oil refinery tends to follow the demand equation below, where x is the number of barrels of oil on hand( in millions) \n" ); document.write( "P = \n" ); document.write( ": \n" ); document.write( "A) how much should be charged for a barrel of oil on hand \n" ); document.write( "One barrel of oil on hand ( in millions) \n" ); document.write( "P = \n" ); document.write( "P = -.20 + 140 \n" ); document.write( "P = $139.80 \n" ); document.write( ": \n" ); document.write( "B) what quantity x will maximize revenue? \n" ); document.write( "Rev = quantity * price \n" ); document.write( "R = x( \n" ); document.write( "R = \n" ); document.write( "This is a quadratic equation; max occurs at he axis of Symmetry, x = -b/(2a) \n" ); document.write( "therefore \n" ); document.write( "x = \n" ); document.write( "x = +350 million barrels of oil on hand for max revenue \n" ); document.write( "\"what is the maximum revenue?' \n" ); document.write( "Find the price when 350 m barrels are on hand \n" ); document.write( "P = \n" ); document.write( "P = -70 + 140 \n" ); document.write( "P = $70 a barrel for max rev \n" ); document.write( "Max revenue: 70 * 350 million = $24,500 million \n" ); document.write( ": \n" ); document.write( "C) what price should be charged in order to maximize revenue \n" ); document.write( "$70 a barrel \n" ); document.write( " \n" ); document.write( " |