document.write( "Question 934958: find three consecutive odd intergers such that twice the sumof the first and third more than the second by fifteen \n" ); document.write( "

Algebra.Com's Answer #568172 by algebrahouse.com(1659) $\"\"$ $\"About$

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x = 1st odd consecutive odd integer
\n" ); document.write( "x + 2 = 2nd consecutive odd integer {odd integers increase by 2}
\n" ); document.write( "x + 4 = 3rd consecutive odd integer\r
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\n" ); document.write( "\n" ); document.write( "2(x + x + 4) = x + 2 + 15 {twice the sum of first and third is more than second by 15}
\n" ); document.write( "2(2x + 4) = x + 17 {combined like terms}
\n" ); document.write( "4x + 8 = x + 17 {used distributive property}
\n" ); document.write( "3x = 9 {subtracted x and subtracted 8 from each side}
\n" ); document.write( "x = 3 {divided each side by 3}
\n" ); document.write( "x + 2 = 5 {substituted 3, in for x, into x + 2}
\n" ); document.write( "x + 4 = 7 {substituted 3, in for x, into x + 4}\r
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\n" ); document.write( "\n" ); document.write( "3,5, and 7 are the three consecutive odd integers
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