document.write( "Question 935000: Given that m∠IHJ = (2x + 17)° and m∠KHJ = (5x − 10)°, identify m∠IHK. \r
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\n" ); document.write( "\n" ); document.write( "m∠IHK = 70°
\n" ); document.write( " m∠IHK = 55°
\n" ); document.write( " m∠IHK = 35°
\n" ); document.write( " m∠IHK = 25°\r
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Algebra.Com's Answer #568147 by MathLover1(20850)\"\" \"About 
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Given that m < \"IHJ+=+%282x+%2B+17%29\"° and m <\"+KHJ+=+%285x+-10%29\"°, \r
\n" ); document.write( "\n" ); document.write( "identify m < \"IHK\"\r
\n" ); document.write( "\n" ); document.write( "\"IJ=JK\" => m < \"IHJ\" = m < \"KHJ\" \r
\n" ); document.write( "\n" ); document.write( "\"2x+%2B+17=+5x+-10\" solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"10%2B+17=+5x+-2x\" \r
\n" ); document.write( "\n" ); document.write( "\"27=+3x\" \r
\n" ); document.write( "\n" ); document.write( "\"27%2F3=+x\" \r
\n" ); document.write( "\n" ); document.write( "\"9=+x\" \r
\n" ); document.write( "\n" ); document.write( "then
\n" ); document.write( " m < \"IHJ+=+2x+%2B+17\"° =>m < \"IHJ+=+2%2A9+%2B+17\"°=>m < \"IHJ+=+18%2B+17\"° =>m < \"IHJ+=+35\"°\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "m < \"KHJ+=+5%2A9+-10\"° => m < \"KHJ+=+45+-10\"° m < \"KHJ+=+35\"° \r
\n" ); document.write( "\n" ); document.write( "identify m < \"IHK\"\r
\n" ); document.write( "\n" ); document.write( "m < \"IHK\"=m < \"IHJ\"+ m < \"KHJ\" or m < \"IHK\"=2*m < \"IHJ\"\r
\n" ); document.write( "\n" ); document.write( "m < \"IHK=2%2A35\"°=> m < \"highlight%28IHK=70%29\"°\r
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