document.write( "Question 933994: The problem involves constructing a rectangular planter.
\n" ); document.write( "The area of the bottom needs to be 90 ft sq.
\n" ); document.write( "Length of planter needs to be three feet longer than twice its width.
\n" ); document.write( "What should the dimensions of the bottom of the planter be?\r
\n" ); document.write( "\n" ); document.write( "This is an 8th grade algebra problem.
\n" ); document.write( "We know the given answer is 6 ft by 15 ft.
\n" ); document.write( "How do we factor this? We are trying to figure the structure of solving the problem.
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Algebra.Com's Answer #568105 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
For a rectangle,
\n" ); document.write( "\"A=L%2AW\"
\n" ); document.write( "\"L%2AW=90\"
\n" ); document.write( "Length of planter needs to be three feet longer than twice its width
\n" ); document.write( "\"L=3%2B2W\"
\n" ); document.write( "Substitute into the area equation,
\n" ); document.write( "\"%283%2B2W%29W=90\"
\n" ); document.write( "\"2W%5E2%2B3W=90\"
\n" ); document.write( "\"2W%5E2%2B3W-90=0\"
\n" ); document.write( "\"%28W-6%29%282W%2B15%29=0\"
\n" ); document.write( "Only the positive solution makes sense here.
\n" ); document.write( "\"W-6=0\"
\n" ); document.write( "\"W=6\"
\n" ); document.write( "Then,
\n" ); document.write( "\"L=3%2B2%286%29\"
\n" ); document.write( "\"L=3%2B12\"
\n" ); document.write( "\"L=15\"
\n" ); document.write( "
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