document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934207>Question 934207</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Complete the identity below:\r<BR>\n" );
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document.write( "(csc (x+1)(csc x-1)<BR>\n" );
document.write( "__________________  = ?<BR>\n" );
document.write( "cot^2 x </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568099 by </B><A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><B>gsmani_iyer(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=gsmani_iyer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=gsmani_iyer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568099\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">   \r<BR>\n" );
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document.write( "   By simplification, the numerator equals csc^2 x - 1 which is equals to cot^2 x.\r<BR>\n" );
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document.write( "   Therefore, (cot^2 x) upon (cot^2 x) = 1\r<BR>\n" );
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document.write( "   I hope this is clear enough. Feel free to contact for further doubts. </SPAN>\n" );
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