document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935023>Question 935023</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If 4 consecutive odd integers sum to 152, what is the smallest of the 4?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568089 by </B><A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><B>AlgebraLady88(44)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=AlgebraLady88><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=AlgebraLady88><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568089\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the first odd integer be x.<BR>\n" );
document.write( "The second one would be x+2<BR>\n" );
document.write( "The third one would be x+4<BR>\n" );
document.write( "The fourth one would be x+6.\r<BR>\n" );
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document.write( "How do I know the second one is x+2? Just plug in 1 as the odd integer(x). For the second one, x+2= 3, then x+4= 5 and the last one, x+6=7. Try it with other odd integers and you will get the same results.\r<BR>\n" );
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document.write( "Now, we can solve algebraically\r<BR>\n" );
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document.write( "x+ (x+2) + (x+4) + (x+6)   = 152<BR>\n" );
document.write( "4x + 12                    = 152<BR>\n" );
document.write( "4x + 12 - 12               = 152-12<BR>\n" );
document.write( "4x                         = 140<BR>\n" );
document.write( "x                          = 35\r<BR>\n" );
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document.write( "So, the integers are 35, 37, 39 and 41. The smallest would be 35.\r<BR>\n" );
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