document.write( "Question 934918: Birth weights at a local hospital have a normal distribution with a mean weight of 110 ounces and a standard deviation of 15 ounces. Using the unit normal table (and leaving off the percentage signs):\r
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document.write( "a. What percent of infants have weights greater than 120 ounces? \r
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document.write( "b. What percent of infants have weights between 95 ounces and 125 ounces? \r
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document.write( "c. What birth weight value separates the lowest 2.5% of infants from the rest? \n" );
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Algebra.Com's Answer #568073 by ewatrrr(24785)![]() ![]() You can put this solution on YOUR website! mean = 110 oz, SD = 15 ounces, \n" ); document.write( ".... \n" ); document.write( "P( x > 120) = P( z > 10/15) = normalcdf( 2/3, 100) = .2525 \n" ); document.write( "P(95 < x < 125) = P( -15/15 < z < 15/15) = normaldcdf(-1,1)= .6827 \n" ); document.write( "... \n" ); document.write( " What birth weight value separates the lowest 2.5% of infants from the rest? \n" ); document.write( "z = invNorm(.025) = -1.96 \n" ); document.write( ".... \n" ); document.write( "(15)(-1.96) + 110 = x = 80.6 oz \n" ); document.write( "round as directed\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |