document.write( "Question 935022: Tanya is four years older than Jason.
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document.write( "In one year, Tanya will be twice jasons age. \n" );
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Algebra.Com's Answer #568054 by algebrahouse.com(1659)![]() ![]() You can put this solution on YOUR website! x = Jason's age now \n" ); document.write( "x + 4 = Tanya's age now {Tanya is 4 years older than Jason}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 1 = Jason's age in one year \n" ); document.write( "x + 5 = Tanya's age in one year\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x + 5 = 2(x + 1) {in four years, Tanya will be twice Jason} \n" ); document.write( "x + 5 = 2x + 2 {used distributive property} \n" ); document.write( "x = 3 {subtracted x and subtracted 2 from each side} \n" ); document.write( "x + 4 = 7 {substituted 3, in for x, into x + 4}\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Jason is 3 \n" ); document.write( "Tanya is 7 \n" ); document.write( " For more help from me, visit: www.algebrahouse.com \n" ); document.write( " |