document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=935021>Question 935021</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the sum of two numbers is 63. the first number is 2/3 of the second number. what is the number </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568053 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568053\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = second number<BR>\n" );
document.write( "(2/3)x = first number   {first number is 2/3 of the second}\r<BR>\n" );
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document.write( "x + (2/3)x = 63   {sum of the two numbers is 63}<BR>\n" );
document.write( "3x + 2x = 189 {multiplied entire equation by 3 to eliminate fraction}<BR>\n" );
document.write( "5x = 189   {combined like terms}<BR>\n" );
document.write( "x = 189/5  {divided each side by 5}<BR>\n" );
document.write( "(2/3)x = 126/5 {substituted 189/5, in for x, into (2/3)x\r<BR>\n" );
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document.write( "first number is 126/5  or   25 1/5<BR>\n" );
document.write( "second number is 189/5  or  37 4/5<BR>\n" );
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