document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934957>Question 934957</A>: <I><SPAN STYLE=\"word-break: break-all;\"> three brothers have ages that are consecutive odd intergers. the difference between the age of the oldest and twice the age of the youngest is twenty four less than the middle brothers age. find their ages </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #568024 by </B><A HREF=/tutors/aboutme.mpl?userid=vicgonzerx><B>vicgonzerx(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vicgonzerx><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=vicgonzerx><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=568024\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> X=YOUNGEST<BR>\n" );
document.write( "X+2=MIDDLE<BR>\n" );
document.write( "X+4=OLDEST\r<BR>\n" );
document.write( "\n" );
document.write( "X+4-2X=X+2-24<BR>\n" );
document.write( "2X=26<BR>\n" );
document.write( "X=13<BR>\n" );
document.write( "X+2=15<BR>\n" );
document.write( "X+4=17\r<BR>\n" );
document.write( "\n" );
document.write( "THE AGE ARE 13,15,17 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );