document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934898>Question 934898</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company.  As a preliminary study, a random sample of 50 freshly caught salmon is weighed.  The sample standard deviation is 2.15 pounds.  How large a sample should be taken to be 99% confident that the sample mean is within 0.20 pound of the true mean weight? <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567984 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567984\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A wildlife study is designed to find the mean weight of salmon caught by an Alaskan fishing company. As a preliminary study, a random sample of 50 freshly caught salmon is weighed. The sample standard deviation is 2.15 pounds. How large a sample should be taken to be 99% confident that the sample mean is within 0.20 pound of the true mean weight? <BR>\n" );
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document.write( "sample std = s/sqrt(50) = 2.15 implies that s = 2.15*sqrt(50) = 15.20<BR>\n" );
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document.write( "n = [z*s/E]^2<BR>\n" );
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document.write( "n = [2.5758*15.20/0.2]^2 = 38,323<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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