document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934559>Question 934559</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 2005, the mean score on the verbal portion of the SAT for college-bound seniors was 508 with a standard deviation of 113. Assume the test scores are normally distributed. \r<BR>\n" );
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document.write( "a. What percent of the SAT verbal scores are less than 590?\r<BR>\n" );
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document.write( "b. If 1200 SAT verbal scores are randomly selected, about how many would you expect to be greater than 525? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567930 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567930\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a) calculate z-score for 590<BR>\n" );
document.write( "z-score = (590 - 508) / 113 = 0.725663717  approx 0.73<BR>\n" );
document.write( "Pr(X<590) = 0.7673<BR>\n" );
document.write( "b) Pr(X>525) = 1 - Pr(X<525)<BR>\n" );
document.write( "calculate the z-score for 525<BR>\n" );
document.write( "note that the sample size is 1200 > 40, so we can use the population standard deviation<BR>\n" );
document.write( "z-score = (525 - 508) / 113 = 0.150442478 approx 0.15<BR>\n" );
document.write( "Pr(X>525) = 1 - Pr(X<525) = 1 - 0.5596 = 0.4404<BR>\n" );
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