document.write( "Question 934844: If f(x) = log3 (x + 1), what is f−1(2)? \n" ); document.write( "

Algebra.Com's Answer #567884 by MathLover1(20850) $\"\"$ $\"About$

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$\"f%28x%29+=+log%283%2C+%28x+%2B+1%29%29\"$ }, find inverse\r
\n" ); document.write( "\n" ); document.write( "since $\"f%28x%29=y\"$ , we have\r
\n" ); document.write( "\n" ); document.write( " $\"y+=+log%283%2C+%28x+%2B+1%29%29\"$ ,...swap $\"x\"$ and $\"y\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=+log%283%2C+%28y+%2B+1%29%29\"$ ...solve for $\"y\"$ , change the base\r
\n" ); document.write( "\n" ); document.write( " $\"x=+log%28+%28y+%2B+1%29%29%2Flog%283%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x%2Alog%283%29=+log%28+%28y+%2B+1%29%29\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"log%283%5Ex%29=+log%28+%28y+%2B+1%29%29\"$ ...if log same, then\r
\n" ); document.write( "\n" ); document.write( " $\"3%5Ex=+y+%2B+1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"3%5Ex-1=+y+\"$ \r
\n" ); document.write( "\n" ); document.write( "so, inverse is:\r
\n" ); document.write( "\n" ); document.write( " $\"f%5E%28-1%29+%28x%29+=+3%5Ex-1\"$ \r
\n" ); document.write( "\n" ); document.write( "now find $\"f%5E%28-1%29+%282%29+\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%5E%28-1%29+%282%29+=+3%5E2-1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%5E%28-1%29+%282%29+=+9-1\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"f%5E%28-1%29+%282%29+=+8\"$ \r
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