document.write( "Question 934844: If f(x) = log3 (x + 1), what is f−1(2)? \n" ); document.write( "
Algebra.Com's Answer #567884 by MathLover1(20850)\"\" \"About 
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\"f%28x%29+=+log%283%2C+%28x+%2B+1%29%29\"}, find inverse\r
\n" ); document.write( "\n" ); document.write( "since \"f%28x%29=y\", we have\r
\n" ); document.write( "\n" ); document.write( "\"y+=+log%283%2C+%28x+%2B+1%29%29\",...swap \"x\" and \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=+log%283%2C+%28y+%2B+1%29%29\"...solve for \"y\", change the base\r
\n" ); document.write( "\n" ); document.write( "\"x=+log%28+%28y+%2B+1%29%29%2Flog%283%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%283%29=+log%28+%28y+%2B+1%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"log%283%5Ex%29=+log%28+%28y+%2B+1%29%29\" ...if log same, then\r
\n" ); document.write( "\n" ); document.write( "\"3%5Ex=+y+%2B+1\"\r
\n" ); document.write( "\n" ); document.write( "\"3%5Ex-1=+y+\"\r
\n" ); document.write( "\n" ); document.write( "so, inverse is:\r
\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29+%28x%29+=+3%5Ex-1\"\r
\n" ); document.write( "\n" ); document.write( "now find \"f%5E%28-1%29+%282%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29+%282%29+=+3%5E2-1\"\r
\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29+%282%29+=+9-1\"\r
\n" ); document.write( "\n" ); document.write( "\"f%5E%28-1%29+%282%29+=+8\"\r
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