document.write( "Question 934836: The sum of a two-digit number is 9. The number itself is 12 times the tenth digit minus 6 times the unit digit. Find the number. \n" ); document.write( "
Algebra.Com's Answer #567881 by josgarithmetic(39617)\"\" \"About 
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T, the digit in the tens place
\n" ); document.write( "U, the digit in the ones place
\n" ); document.write( "\"highlight_green%2810T%2BU%29\" is the two-digit number\r
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\n" ); document.write( "\n" ); document.write( "Your first sentence in the problem description is wrong. The sum of a number is just the number itself.
\n" ); document.write( "If this sum is 9, then this does not account for any two-digit number. I will ASSUME you mean that
\n" ); document.write( "the sum of THE DIGITS of the two digit number is 9, and this would be \"T%2BU=9\".\r
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\n" ); document.write( "\n" ); document.write( "Second sentence: \"10T%2BU=12%2AT-6%2AU\", and you mean, \"TENS\" but not \"TENTH\".\r
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\n" ); document.write( "\n" ); document.write( "Your starting system is \"highlight%28system%2810T%2BU=12T-6U%2CT%2BU=9%29%29\".
\n" ); document.write( "Solve the system for T and U.
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