document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79123>Question 79123</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The numbers 1 to 10 are written on sheets of paper and placed in a hat. If two sheets are selected at random then find the following:<BR>\n" );
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document.write( "The probabilit both numbers are ODD with replacement. <BR>\n" );
document.write( "Note: \"with replacement\" assumes the first selection is replaced back into the hat before the second selection is made. <BR>\n" );
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document.write( "A. 1/100<BR>\n" );
document.write( "B. 1/4<BR>\n" );
document.write( "C. 2/9<BR>\n" );
document.write( "D. 1/5<BR>\n" );
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document.write( "The probability both numbers are ODD without replacement.<BR>\n" );
document.write( "Note: \"without replacement\" assumes the first selection is NOT replaced back into the hat, but is held out, while the second selection is made. <BR>\n" );
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document.write( "A. 1/5<BR>\n" );
document.write( "B. 2/9<BR>\n" );
document.write( "C. 1/4<BR>\n" );
document.write( "D. 1/100<BR>\n" );
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document.write( "The probability the first number is ODD and the second number is EVEN without replacement. <BR>\n" );
document.write( "A. 1/4<BR>\n" );
document.write( "B. 5/18<BR>\n" );
document.write( "C. 2/9<BR>\n" );
document.write( "D. 13/18<BR>\n" );
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document.write( "The probability of selecting a 2 and then a 9, with replacement.<BR>\n" );
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document.write( "A 1/4<BR>\n" );
document.write( "B. 5/18<BR>\n" );
document.write( "C. 2/9<BR>\n" );
document.write( "D. 13/18<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56787 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56787\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The numbers 1 to 10 are written on sheets of paper and placed in a hat. If two sheets are selected at random then find the following:\r<BR>\n" );
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document.write( "The probabilit (both numbers are ODD with replacement)=(5/10)(5/10)=1/4 <BR>\n" );
document.write( "Note: \"with replacement\" assumes the first selection is replaced back into the hat before the second selection is made. \r<BR>\n" );
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document.write( "A. 1/100<BR>\n" );
document.write( "B. 1/4<BR>\n" );
document.write( "C. 2/9<BR>\n" );
document.write( "D. 1/5<BR>\n" );
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document.write( "The probability (both numbers are ODD without replacement)=(5/10)(4/9)=2/9\r<BR>\n" );
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document.write( "Note: \"without replacement\" assumes the first selection is NOT replaced back into the hat, but is held out, while the second selection is made. \r<BR>\n" );
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document.write( "A. 1/5<BR>\n" );
document.write( "B. 2/9<BR>\n" );
document.write( "C. 1/4<BR>\n" );
document.write( "D. 1/100<BR>\n" );
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document.write( "The probability (the first number is ODD AND the second number is EVEN without replacement) = (5/10)(5/9)=25/90=5/18 <BR>\n" );
document.write( "A. 1/4<BR>\n" );
document.write( "B. 5/18<BR>\n" );
document.write( "C. 2/9<BR>\n" );
document.write( "D. 13/18<BR>\n" );
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document.write( "The probability <BR>\n" );
document.write( "(of selecting a 2 and then a 9, with replacement)=(1/10)(1/10)=1/100\r<BR>\n" );
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document.write( "A 1/4<BR>\n" );
document.write( "B. 5/18<BR>\n" );
document.write( "C. 2/9<BR>\n" );
document.write( "D. 13/18<BR>\n" );
document.write( "--------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.\r<BR>\n" );
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