document.write( "Question 934803: A collection of 120 coins worth of $5.52 consists of pennies, nickels, dimes and quarters. There are 8 more nickels than dimes and three times as many pennies as nickels. How many of each type of coin are there?\r
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document.write( "What I've tried:
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document.write( " x+y+z+w=120
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document.write( " 1x+5y+10z+25w=552
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document.write( " y=z+8
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document.write( " x=3y
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document.write( "3y+z+8+z+w=120 1(3y)+5(z+8)+10z+25w=552
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document.write( "3y+2z+w=112 3y+5z+40+10z+25w=552
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document.write( " 3y+5z+10z+25w=512
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document.write( " 3y+15z+25w=512
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document.write( "(-36y-24z-12w)=-1344
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document.write( "3y+15z+25w=512
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document.write( "(-33y-9z+13w)=-832 \n" );
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Algebra.Com's Answer #567843 by MathTherapy(10552)![]() ![]() You can put this solution on YOUR website! A collection of 120 coins worth of $5.52 consists of pennies, nickels, dimes and quarters. There are 8 more nickels than dimes and three times as many pennies as nickels. How many of each type of coin are there?\r \n" ); document.write( "\n" ); document.write( "What I've tried: \n" ); document.write( " x+y+z+w=120 \n" ); document.write( " 1x+5y+10z+25w=552 \n" ); document.write( " \n" ); document.write( " y=z+8 \n" ); document.write( " x=3y \n" ); document.write( " \n" ); document.write( "3y+z+8+z+w=120 1(3y)+5(z+8)+10z+25w=552 \n" ); document.write( "3y+2z+w=112 3y+5z+40+10z+25w=552 \n" ); document.write( " 3y+5z+10z+25w=512 \n" ); document.write( " 3y+15z+25w=512 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(-36y-24z-12w)=-1344 \n" ); document.write( "3y+15z+25w=512 \n" ); document.write( "(-33y-9z+13w)=-832 \n" ); document.write( " Due to the fact that it's extremely messy, at times confusing, and doesn't guarantee correct answers,\n" ); document.write( " |