document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=930814>Question 930814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the ages of the two brothers is 20.In five years, one is twice the other. Find the present ages of the two brothers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567821 by </B><A HREF=/tutors/aboutme.mpl?userid=ptfile><B>ptfile(81)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptfile><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptfile><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = the age of the older brother<BR>\n" );
document.write( "y = the age of the younger brother\r<BR>\n" );
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document.write( "The sum of the ages of the two brothers is 20.<BR>\n" );
document.write( "x+y=20<BR>\n" );
document.write( "  y=20-x\r<BR>\n" );
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document.write( "In five years, one is twice the other.<BR>\n" );
document.write( "x+5=2(y+5)<BR>\n" );
document.write( "x+5=2(20-x+5)<BR>\n" );
document.write( "x+5=40-2x+10<BR>\n" );
document.write( "x+5=50-2x<BR>\n" );
document.write( " 3x=45<BR>\n" );
document.write( "  x=15<BR>\n" );
document.write( "  y=5\r<BR>\n" );
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document.write( "The older brother's age is 15 years old while the younger brother's age is 5 years old. </SPAN>\n" );
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