document.write( "Question 79115: at 1:00 p.m., a car leave a city and travels north at a rate of 55mi/h. An hour later, a second care leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart? \n" ); document.write( "

Algebra.Com's Answer #56780 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
The way to read this is that the sum of the distances the cars travel
\n" ); document.write( "is 285 mi.
\n" ); document.write( "I'd like to start them both off at the same time, so the 2nd car has gone
\n" ); document.write( " $\"d+=+60%2A1\"$
\n" ); document.write( " $\"d+=+60\"$ mi when the 1st car begins to move.
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+55%2At%5B1%5D+%2B+60+%2B+60%2At%5B2%5D\"$
\n" ); document.write( "They travel for the same amount of time now, so
\n" ); document.write( " $\"t%5B1%5D+=+t%5B2%5D\"$
\n" ); document.write( " $\"285+=+55t+%2B+60+%2B+60t\"$
\n" ); document.write( " $\"115t+%2B+60+=+285\"$
\n" ); document.write( " $\"115t+=+225\"$
\n" ); document.write( " $\"t+=+45%2F23\"$ hrs
\n" ); document.write( "The time will be 1 pm + 1 hr + 45/23 hrs
\n" ); document.write( "This is 1 pm + 3 hrs - 1/23 hrs, or
\n" ); document.write( "4 pm - 1/23*60 min, or
\n" ); document.write( "3 pm + 57.4 min
\n" ); document.write( "I hope I didn't make a mistake \n" ); document.write( "

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