document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=79115>Question 79115</A>: <I><SPAN STYLE=\"word-break: break-all;\"> at 1:00 p.m., a car leave a city and travels north at a rate of 55mi/h.  An hour later, a second care leaves the city and travels south at a rate of 60 mi/hr.  At what time will the two cars be 285 miles apart? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #56778 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=56778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 55T+60(T-1)=285<BR>\n" );
document.write( "55T+60T-60=285<BR>\n" );
document.write( "115T=285+60<BR>\n" );
document.write( "115T=345<BR>\n" );
document.write( "T=345/115<BR>\n" );
document.write( "T=3 HOURS AFTER THE FIRST CAR LEAVES THEY WILL BE 285 MILES APART.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "55*3+60*2=285<BR>\n" );
document.write( "165+120=285<BR>\n" );
document.write( "285=285  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );