document.write( "Question 934756: The 4th,5th and 6th terms of a linear sequence are 9-2x, x-2 and 2x-1 respectively. Find the:
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Algebra.Com's Answer #567752 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
Let's call the 4th,5th,6th terms: p, q, r\r
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\n" ); document.write( "\n" ); document.write( "p = 9-2x
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\n" ); document.write( "r = 2x-1\r
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\n" ); document.write( "\n" ); document.write( "If we subtract the 4th term from the fifth, we get q - p. That's equal to r - q since we have a common difference\r
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\n" ); document.write( "\n" ); document.write( "q - p = r - q\r
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\n" ); document.write( "\n" ); document.write( "q+q = r+p\r
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\n" ); document.write( "\n" ); document.write( "2q = r+p\r
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\n" ); document.write( "\n" ); document.write( "2(x-2) = (2x-1)+(9-2x)\r
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\n" ); document.write( "\n" ); document.write( "2x - 4 = 2x-1 + 9 - 2x\r
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\n" ); document.write( "\n" ); document.write( "2x - 4 = 8\r
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\n" ); document.write( "\n" ); document.write( "I'll let you finish up.
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