document.write( "Question 934756: The 4th,5th and 6th terms of a linear sequence are 9-2x, x-2 and 2x-1 respectively. Find the:
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document.write( " a) value of x
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document.write( " b) 20th term
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document.write( " c). nth term
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document.write( " d) sum of 5th to 20th terms \n" );
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Algebra.Com's Answer #567752 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! Let's call the 4th,5th,6th terms: p, q, r\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "p = 9-2x \n" ); document.write( "q = x-2 \n" ); document.write( "r = 2x-1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If we subtract the 4th term from the fifth, we get q - p. That's equal to r - q since we have a common difference\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so,\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "q - p = r - q\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "q+q = r+p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2q = r+p\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2(x-2) = (2x-1)+(9-2x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4 = 2x-1 + 9 - 2x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2x - 4 = 8\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll let you finish up. \n" ); document.write( " |