document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934693>Question 934693</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two angles are supplementary one angle is 32 degree less than 3 times the other angle find the angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567749 by </B><A HREF=/tutors/aboutme.mpl?userid=harpazo><B>harpazo(655)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=harpazo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=harpazo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567749\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One angle is x and the other is 180-x.\r<BR>\n" );
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document.write( "x - 32 = 3(180-x)\r<BR>\n" );
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document.write( "x - 32 = 540 - 3x\r<BR>\n" );
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document.write( "-32 - 540 = -3x - x\r<BR>\n" );
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document.write( "-572 = -4x\r<BR>\n" );
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document.write( "-572/-4 = x\r<BR>\n" );
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document.write( "143 degrees = x.\r<BR>\n" );
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document.write( "Then 180 - 143 = 37 degrees.\r<BR>\n" );
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document.write( "The two angles are 37 degrees and 143 degrees.  </SPAN>\n" );
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