document.write( "Question 934588: The area of a rectangle is 55yds. squared, and the length of the rectangle is 4yds less than three times the width. Find the dimensions of the rectangle. \n" ); document.write( "

Algebra.Com's Answer #567732 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi,
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document.write( "     .
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document.write( "L = 3w-4
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document.write( "A = Lw
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document.write( "(3w-4)w = 55 yd^2
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document.write( "3w^2 - 4w - 55 = 0  (tossing out negative solution for unit measure)
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document.write( "(3w+11)(w-5) = 0
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document.write( "w = 5 yd  and L = 11yd 
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document.write( "And...checking
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document.write( "(11yd)(5yd) = 55yd^2 \n" );
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