document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934669>Question 934669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express y in terms of x , it being given that 3x+y-12=0.Check whether the point (3,3) is on the line represented by the equation 3x+y-12=0. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567677 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567677\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3x + y -12 = 0<BR>\n" );
document.write( "subtract 3x from both sides of =<BR>\n" );
document.write( "y - 12 = -3x<BR>\n" );
document.write( "add 12 to both sides of =<BR>\n" );
document.write( "y = -3x + 12<BR>\n" );
document.write( "the problem asks if the point (3,3) is on the line, substitute for x and y<BR>\n" );
document.write( "3 = -3*3 +12<BR>\n" );
document.write( "3 = -9 + 12<BR>\n" );
document.write( "3 = 3<BR>\n" );
document.write( "therefore the point (3,3) lies on the line y = -3x + 12<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );