document.write( "Question 934682: Hope you can help me! :)\r
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document.write( "When Neil was 2 miles upstream from camp on a canoe trip, he passed a log floating downstream with the current. He paddled upstream for 1 more hour and then returned to camp just as the log arrived. What was the rate of the current?
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Algebra.Com's Answer #567675 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let rate of canoe be x mph \n" ); document.write( "rate of current = y\r \n" ); document.write( "\n" ); document.write( "Time taken by log to reach starting point = 2/y.....................(1)\r \n" ); document.write( "\n" ); document.write( "he canoes for 1 hour at speed of (x-y) upstream\r \n" ); document.write( "\n" ); document.write( "so distance he paddles = x-y\r \n" ); document.write( "\n" ); document.write( "Return\r \n" ); document.write( "\n" ); document.write( "downstream speed = (x+y)\r \n" ); document.write( "\n" ); document.write( "Time taken to reach starting point = time to reach the crossing point + time taken for 2 miles \n" ); document.write( "=(x-y)/(x+y) +2/(x+y)\r \n" ); document.write( "\n" ); document.write( "2/y = 1+(x-y)/(x+y) +2/(x+y)\r \n" ); document.write( "\n" ); document.write( "2/y = (x+y+x-y+2)/(x+y)\r \n" ); document.write( "\n" ); document.write( "2/y = (2x+2)/(x+y)\r \n" ); document.write( "\n" ); document.write( "2/y = 2(x+2)/(x+y)\r \n" ); document.write( "\n" ); document.write( "1/y =(x+1)/(x+y)\r \n" ); document.write( "\n" ); document.write( "x+y = xy+y\r \n" ); document.write( "\n" ); document.write( "x=xy\r \n" ); document.write( "\n" ); document.write( "y=1\r \n" ); document.write( "\n" ); document.write( "rate of current = 1mph\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |