document.write( "Question 79106: I need to solve for w and find the solution set for the following: Sqrt (5w-1) = w-3. I multiplied both sides by sqrt (5w-1) and got (5w-1) = w-3(sqrt (5w-1). \n" ); document.write( "
Algebra.Com's Answer #56764 by Earlsdon(6294)\"\" \"About 
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Solve for w:
\n" ); document.write( "\"sqrt%285w-1%29+=+w-3\" Square both sides.
\n" ); document.write( "\"5w-1+=+w%5E2-6w%2B9\" Subtract 5w from both sides.
\n" ); document.write( "\"-1+=+w%5E2-11w%2B9\" Add 1 to both sides.
\n" ); document.write( "\"0+=+w%5E2-11w%2B10\" Factor this quadratic equation.
\n" ); document.write( "\"0+=+%28w-1%29%28w-10%29\" Apply the zero products principle:
\n" ); document.write( "\"w-1+=+0\" or \"w-10+=+0\" so...
\n" ); document.write( "\"w+=+1\" or \"w+=+10\"
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