document.write( "Question 78590: Joe is 10 years older than James. In 8 years, twice Joe's age will equal three times James's age. How old is each now?\r
\n" ); document.write( "\n" ); document.write( "{James is yrs., Joe is yrs.}\r
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Algebra.Com's Answer #56762 by attaboy15(1)\"\" \"About 
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Joe is 10 years older than James. In 8 years twice Joe’s age will equal 3 times James age.
\n" ); document.write( "What are their ages now?\r
\n" ); document.write( "\n" ); document.write( "First, let’s determine their ages 8 years from now. Once that is determined, then we can just subtract 8 years from the answer to get their ages now. \r
\n" ); document.write( "\n" ); document.write( "If Joe’s age is X then James age is X-10\r
\n" ); document.write( "\n" ); document.write( "Here is the first equation to use.\r
\n" ); document.write( "\n" ); document.write( "2 times X = 3 times ( X – 10 ) or \r
\n" ); document.write( "\n" ); document.write( "2X=3(X-10) this can become the following
\n" ); document.write( "2X=3X-30 add 30 to each side and get the following
\n" ); document.write( "2X+30=3X now subtract 2X from each side and get
\n" ); document.write( "30=3X-2X 3X – 2X = 1X or just X so…..
\n" ); document.write( "30=X\r
\n" ); document.write( "\n" ); document.write( "So Joe’s age in 8 years is 30, James would be 20 (10 years younger) but their ages now would be\r
\n" ); document.write( "\n" ); document.write( "Joe - 30-8=22
\n" ); document.write( "James – 20-8=12
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