document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934218>Question 934218</A>: <I><SPAN STYLE=\"word-break: break-all;\"> You want to make an investment in a continuously compounding account over a period of 100 years. What interest rate is required for your investment to double in that time period? Round the logarithm value and the answer to the nearest hundredth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567597 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567597\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You want to make an investment in a continuously compounding account over a period of 100 years. What interest rate is required for your investment to double in that time period? Round the logarithm value and the answer to the nearest hundredth.<BR>\n" );
document.write( "..<BR>\n" );
document.write( "formula for continous compounding: A=pe^rt, p=initial investment, r=interest rate, t=years, A=amount after t-years<BR>\n" );
document.write( "..<BR>\n" );
document.write( "A/p=2=e^rt<BR>\n" );
document.write( "rtlne=ln2<BR>\n" );
document.write( "lne=1<BR>\n" );
document.write( "rt=ln2<BR>\n" );
document.write( "r=ln2/t<BR>\n" );
document.write( "r=ln2/100=0.69<BR>\n" );
document.write( "What interest rate is required for your investment to double in 100 yrs? 0.69%                </SPAN>\n" );
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