document.write( "Question 934601: How am I supposed to answer this question im supposed to show my work and give the proof. my teacher tried showing me but I still don't get it. Question: If AC=BD, then AB=CD \n" ); document.write( "
Algebra.Com's Answer #567592 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
AC=BD, then AB=CD\r
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\n" ); document.write( "\n" ); document.write( " From the above figure we get that
\n" ); document.write( "\"AC+++++=+AB+%2B+BC\"
\n" ); document.write( "\"BD+++++=+BC+%2B+CD\"\r
\n" ); document.write( "\n" ); document.write( "It is given that \"AC+=+BD\"- if left sides equal, then right sides are equal too; so, we get:\r
\n" ); document.write( "\n" ); document.write( "\"AB+%2B+BC++++++=+BC+%2B+CD\" … (1)\r
\n" ); document.write( "\n" ); document.write( "According to Euclid’s axiom,when equals are subtracted from equals, the remainders are also equal.\r
\n" ); document.write( "\n" ); document.write( "Subtracting \"BC\" from both side in equation (1), we get\r
\n" ); document.write( "\n" ); document.write( "\"AB+%2B+BC-BC++++=+BC+%2B+CD+-BC\"\r
\n" ); document.write( "\n" ); document.write( "\"AB+++++=+CD\" .........=>Hence proved.\r
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