document.write( "Question 934569: this is a yes or no question.....\r
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document.write( "A car travels a 1-mile track at an average speed of 15 mph. Is it possible for the car to travel the next mile so that the average speed for the 2 mi is 30 mph?\r
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document.write( " thanks so much for the help!!
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Algebra.Com's Answer #567578 by DrBeeee(684)![]() ![]() ![]() You can put this solution on YOUR website! Answer: No \n" ); document.write( "Why, you ask? \n" ); document.write( "Let's figure it out. \n" ); document.write( "Let d = rt, with rate r in mph and t in hrs, then d is miles. \n" ); document.write( "The time to travel the first mile is \n" ); document.write( "(1) t1 = d/r or \n" ); document.write( "(2) t1 = 1/15 \n" ); document.write( "Let the rate for the second mile be x, then the time for the second mile is \n" ); document.write( "(3) t2 = 1/x \n" ); document.write( "The average speed (rate) for the two miles is \n" ); document.write( "(4) rave = d/t or \n" ); document.write( "(5) rave = 2/(t1+t2) or \n" ); document.write( "(6) rave = 2/(1/15 + 1/x) \n" ); document.write( "We are asked if rave can be 30mph. Let's see. Can (6) be equal to 30? \n" ); document.write( "(7) 30 = 2/(1/15 + 1/x) or \n" ); document.write( "(8) 30 = 2/(x + 15)/(15x) or \n" ); document.write( "(9) 30 = 30x/(x + 15) or \n" ); document.write( "(10) 1 = x/(x + 15) or \n" ); document.write( "(11) (x + 15) = x or \n" ); document.write( "(12) 15 = 0 \n" ); document.write( "I don't recall that 15 = 0, do you? \n" ); document.write( "So it is impossible. You need to travel the second mile in zero time. then we have in (5) \n" ); document.write( "(13) rave = 2/(t1+t2) or \n" ); document.write( "(14) rave = 2/(1/15+0) or \n" ); document.write( "(15) rave = 2/(1/15) or \n" ); document.write( "(16) rave = 30 \n" ); document.write( "It means that we travel at an infinite rate to take zero seconds! \n" ); document.write( "You're welcome.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |