document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934574>Question 934574</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 9ln(3x)=21 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567566 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567566\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given;<BR>\n" );
document.write( "(1) 9ln(3x) = 21<BR>\n" );
document.write( "Divide through by 9 and get<BR>\n" );
document.write( "(2) ln(3x) = 21/9<BR>\n" );
document.write( "Now take the inverse ln of each side to get<BR>\n" );
document.write( "(3) 3x = invln(21/9) or<BR>\n" );
document.write( "(4) 3x = 10.312258... and<BR>\n" );
document.write( "(5) x = 3.437419...<BR>\n" );
document.write( "We can express the answer exactly in terms of e, as follows;<BR>\n" );
document.write( "Using (2), we have <BR>\n" );
document.write( "(6) ln(3x) = 7/3 or<BR>\n" );
document.write( "(7) 3x = invln(7/3) or<BR>\n" );
document.write( "(8) 3x = e^(7/3) or<BR>\n" );
document.write( "(9) x = (1/3)e^(7/3) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );