document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934571>Question 934571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 13. What is the missing term in the geometric sequence?<BR>\n" );
document.write( "3/4, 1/2, 1/3, [?], 4/27, 8/81  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567556 by </B><A HREF=/tutors/aboutme.mpl?userid=DrBeeee><B>DrBeeee(684)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=DrBeeee><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A geometric series is one in which the RATIO of sequential terms is a CONSTANT.<BR>\n" );
document.write( "To find the constant simply divide the second term of the sequence by the first term. <BR>\n" );
document.write( "Given;<BR>\n" );
document.write( "S = {3/4,1/2,1/3,?,4/27,8/81}<BR>\n" );
document.write( "The constant is<BR>\n" );
document.write( "(1) c = (1/2)/(3/4) or<BR>\n" );
document.write( "(2) c = (1/2)*(4/3) or<BR>\n" );
document.write( "(3) c = (1*4)/(2*3) or<BR>\n" );
document.write( "(4) c = 4/6 or<BR>\n" );
document.write( "(5) c = 2/3<BR>\n" );
document.write( "Now check your sequence<BR>\n" );
document.write( "S = {3/4, (2/3*(3/4)= 1/2, (2/3)*(1/2) = 1/3, ? = (2/3)*(1/3) = 2/9, (2/3)*(2/9) = 4/27, (2/3)*(4/27) = 8/81}<BR>\n" );
document.write( "Answer: The missing (?) term is 2/9 </SPAN>\n" );
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