document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934557>Question 934557</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The number of vacation days taken by employees of a company is normally distributed with a mean of 14 days and a standard deviation of 3 days. For the next employee, what is the probability that the number of days of vacation taken is less than 10 days? More than 21 days? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567550 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567550\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The number of vacation days taken by employees of a company is normally distributed with a mean of 14 days and a standard deviation of 3 days. For the next employee, what is the probability that the number of days of vacation taken is less than 10 days?<BR>\n" );
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document.write( "z(10) = (10-14)/3 = -4/3<BR>\n" );
document.write( "P(x < 10) = P(z < -4/3) = normalcdf(-100,-4/3) = 0.09121 \r<BR>\n" );
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document.write( "More than 21 days?<BR>\n" );
document.write( "z(21) = (21-14)/3 = 7/3<BR>\n" );
document.write( "P(x > 21) = P(z > 7/3) = normalcdf(7/3,100) = 0.00982<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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