document.write( "Question 934515: Solve for x:
\n" ); document.write( "e^(x)+e^(2x)=12
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Algebra.Com's Answer #567513 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"e%5Ex%2Be%5E%282x%29=12\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5Ex%2Be%5Ex%2Ae%5Ex=12\"\r
\n" ); document.write( "\n" ); document.write( "\"e%5Ex%2A%28e%5Ex%2B1%29+=3%2A4\"\r
\n" ); document.write( "\n" ); document.write( "if product same then corresponding factors are same too; so, we have\r
\n" ); document.write( "\n" ); document.write( "\"e%5Ex=+3\"\r
\n" ); document.write( "\n" ); document.write( "and\r
\n" ); document.write( "\n" ); document.write( "\"e%5Ex%2B1+=+4\"=>\"e%5Ex+=+4-1\"=>\"e%5Ex=+3\"\r
\n" ); document.write( "\n" ); document.write( "\"log%28e%5Ex%29=+log%283%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%2Alog%28e%29=+log%283%29\"......\"log%28e%29=1\"\r
\n" ); document.write( "\n" ); document.write( "\"x+=+log%283%29\"
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