document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=10815>Question 10815</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Roz is twice as old as Grace. In 5 years the sum of their ages will be 28. How old are they now? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #5675 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=5675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let R be Roz's present age and G be Grace's present age.\r<BR>\n" );
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document.write( "1) R = 2G\r<BR>\n" );
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document.write( "2) R+5 + G+5 = 28  Substitute R = 2G and solve for G.\r<BR>\n" );
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document.write( "2G+5 + G+5 = 28 Simplify and solve for G.<BR>\n" );
document.write( "3G + 10 = 28 Subtract 10 from both sides.<BR>\n" );
document.write( "3G = 18 Divide both sides by 3.<BR>\n" );
document.write( "G = 6\r<BR>\n" );
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document.write( "R = 2G<BR>\n" );
document.write( "R = 12\r<BR>\n" );
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document.write( "Roz is 12 years old.<BR>\n" );
document.write( "Grace is 6 years old. </SPAN>\n" );
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