document.write( "Question 934477: Two numbers have a sum = 67. The larger number is \"one less than three times the smaller number. Find the two numbers. \n" ); document.write( "
Algebra.Com's Answer #567473 by BigToosie(32)![]() ![]() ![]() You can put this solution on YOUR website! x + y = 67 \n" ); document.write( "x = 3y - 1 \n" ); document.write( "substitute second equation into first equation: \n" ); document.write( "3y - 1 + y = 67 \n" ); document.write( "combine like terms: \n" ); document.write( "4y = 68 \n" ); document.write( "divide both sides by 4: \n" ); document.write( "y = 68/4 = 17 \n" ); document.write( "using second equation: \n" ); document.write( "x = 3(17) - 1 = 50 \n" ); document.write( "check using first equation: \n" ); document.write( "50 + 17 = 67 checks \n" ); document.write( "The numbers are 50 and 17. \n" ); document.write( " |