document.write( "Question 934444: If Ram walks from his house at 5 kmph, he reaches school 5 min early, and if he walks at 4 kmph he reaches 5 min late. What is the actual distance between \n" ); document.write( "
Algebra.Com's Answer #567441 by mananth(16946)\"\" \"About 
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If Ram walks from his house at 5 kmph, he reaches school 5 min early, and if he walks at 4 kmph he reaches 5 min late. What is the actual distance between\r
\n" ); document.write( "\n" ); document.write( "let the distance be x
\n" ); document.write( "and his normal speed be y\r
\n" ); document.write( "\n" ); document.write( "normal time = x/y \r
\n" ); document.write( "\n" ); document.write( "Condition I
\n" ); document.write( "5 minutes = 5/60 = 1/12 hours\r
\n" ); document.write( "\n" ); document.write( "speed = 5 kmph
\n" ); document.write( "time = x/5
\n" ); document.write( "x/y -x/5 = 1/12\r
\n" ); document.write( "\n" ); document.write( "Condition II\r
\n" ); document.write( "\n" ); document.write( "x/4 -x/y =1/12\r
\n" ); document.write( "\n" ); document.write( "Add the two equatations\r
\n" ); document.write( "\n" ); document.write( "x/4 -x/5 = 1/12 + 1/12\r
\n" ); document.write( "\n" ); document.write( "x/20 = 2/12\r
\n" ); document.write( "\n" ); document.write( "x/20 = 1/6
\n" ); document.write( "x=20/6\r
\n" ); document.write( "\n" ); document.write( "x=3.33 km
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