document.write( "Question 934331: Jason drove 150 km at 100 km/hr to a stampede. Then she drove back home at 80 km/hr. What is the difference in time between the trips. Explain \n" ); document.write( "
Algebra.Com's Answer #567432 by TimothyLamb(4379)\"\" \"About 
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a = time going
\n" ); document.write( "b = time returning
\n" ); document.write( "---
\n" ); document.write( "s = d/t
\n" ); document.write( "t = d/s
\n" ); document.write( "---
\n" ); document.write( "time going:
\n" ); document.write( "a = 150/100
\n" ); document.write( "---
\n" ); document.write( "time returning:
\n" ); document.write( "b = 150/80
\n" ); document.write( "---
\n" ); document.write( "b - a = 150/80 - 150/100
\n" ); document.write( "b - a = 0.375 hours
\n" ); document.write( "b - a = (0.375 hours) * (60 minutes/hour)
\n" ); document.write( "b - a = 22.5 minutes
\n" ); document.write( "---
\n" ); document.write( "answer:
\n" ); document.write( "it took 22.5 minutes more to return than it did to go, due to the slower return speed
\n" ); document.write( "---
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