document.write( "Question 934380: Find the tan(alpha-beta), if sin alpha=-5/13, cos beta=15/17, 3pie/2
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Algebra.Com's Answer #567426 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Find the tan(alpha-beta), if sin alpha=-5/13, cos beta=15/17, 3pie/2 \n" ); document.write( "reference angle a is in quadrant IV where sin<0, cos>0 \n" ); document.write( "sina=-5/13 \n" ); document.write( "cosa=12/13 \n" ); document.write( "tana=sin/cos=-5/12 \n" ); document.write( ".. \n" ); document.write( "reference angle b is in quadrant I where sin>0, cos>0 \n" ); document.write( "cosb=15/17 \n" ); document.write( "sinb=8/17 \n" ); document.write( "tanb=8/15 \n" ); document.write( ".. \n" ); document.write( "tan(a+b)=(tana+tanb)/(1-tana*tanb) \n" ); document.write( "=(-5/12+8/15)/1-(-5/12)*8/15 \n" ); document.write( "=(-25/60+32/60)/(1+40/180) \n" ); document.write( "=(7/60)/1+(2/9)=7/60/11/9=63/660 \n" ); document.write( "tan(a+b)=63/660 |