document.write( "Question 934389: I need help solving a problem, i get to a certain point and get stuck. \"log+%285%2Cx%29%2Blog+%285%2C+4x-1%29=1\" I get as far as writing the equation in standard formula and the using the quadratic equation but I think that is where I'm messing up and getting stuck. \n" ); document.write( "
Algebra.Com's Answer #567392 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
You have no quadratic equation.\r
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\n" ); document.write( "\n" ); document.write( "\"log+%285%2Cx%29%2Blog+%285%2C+%284x-1%29%29=1\", what your actual text really shows inside the rendering tags;\r
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\n" ); document.write( "\n" ); document.write( "\"log%285%2C%28x%284x-1%29%29%29=1\"\r
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\n" ); document.write( "\n" ); document.write( "The LOGARITHM is the EXPONENT.
\n" ); document.write( "The BASE used is 5.
\n" ); document.write( "Change into exponential form.\r
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\n" ); document.write( "\n" ); document.write( "\"5%5E1=x%284x-1%29\", which you should have no further trouble to solve.\r
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\n" ); document.write( "The rendering does not always clarify certain things. Your original text was log (5,x)+log (5, 4x-1)=1
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\n" ); document.write( "You clearly want \"4x-1\" to be the expression in a logarithm function. I then included left and right parentheses around the expression, which ensured that the -1 part would appear in the intended position; otherwise, your original text makes the -1 appear to be outside the logarithm function, which would NOT be what you intended. I had planned to ADD 1 to left and right sides of the equation and this would have been in disagreement with your equation.
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