document.write( "Question 934386: Hello. I have a question on my study guide that I can't answer (because math is my most complicated subject and I am very confused). I have a final tomorrow and my teacher hasn't gone over this question yet. \"The length of a photograph is 4 in. greater than its width. The area of the photograph is 52 1/4 in.^2. What are the dimensions of the photograph?\" \n" ); document.write( "
Algebra.Com's Answer #567391 by mananth(16946)![]() ![]() You can put this solution on YOUR website! width = x \n" ); document.write( "length =x+4 in\r \n" ); document.write( "\n" ); document.write( "Area = L*w\r \n" ); document.write( "\n" ); document.write( "Area = 52 1/4 = 209/4 \r \n" ); document.write( "\n" ); document.write( "x(x+4) = 209/4 \r \n" ); document.write( "\n" ); document.write( "x^2+4x = 209/4\r \n" ); document.write( "\n" ); document.write( "x^2+4x+4 = 209/4 +4\r \n" ); document.write( "\n" ); document.write( "(x+2)^2= 225/4\r \n" ); document.write( "\n" ); document.write( "(x+2)= +/-(15/2)\r \n" ); document.write( "\n" ); document.write( "x+2 = +/- 7.5\r \n" ); document.write( "\n" ); document.write( "x= 7.5-2 = 5.5\r \n" ); document.write( "\n" ); document.write( "ignore negative value\r \n" ); document.write( "\n" ); document.write( "width = 5.5 in \n" ); document.write( "length = 9.5 in\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |