document.write( "Question 934382: The base-path of a baseball diamond form a square. If it is 90 ft from home to first, how far does the catcher have to throw to catch someone stealing second base? plz helppppp \n" ); document.write( "
Algebra.Com's Answer #567377 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
a^2 + b^2 = c^2 ... pythagorean theorem\r
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\n" ); document.write( "\n" ); document.write( "90^2 + 90^2 = c^2\r
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\n" ); document.write( "\n" ); document.write( "8100 + 8100 = c^2\r
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\n" ); document.write( "\n" ); document.write( "2*8100 = c^2\r
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\n" ); document.write( "\n" ); document.write( "c^2 = 2*8100\r
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\n" ); document.write( "\n" ); document.write( "c = sqrt(2*8100)\r
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\n" ); document.write( "\n" ); document.write( "c = sqrt(2)*sqrt(8100)\r
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\n" ); document.write( "\n" ); document.write( "c = sqrt(2)*90\r
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\n" ); document.write( "\n" ); document.write( "c = 90*sqrt(2)\r
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\n" ); document.write( "\n" ); document.write( "The exact distance is \"90sqrt%282%29\" which approximates to 127.2792 feet.\r
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\n" ); document.write( "\n" ); document.write( "Jim\r
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