document.write( "Question 934291: Please help me solve this question: Pipe A can fill a tank in 5 h. Pipe B can fill it in 2 h less time than it takes Pipe C, a drainpipe, to empty the tank. With all three pipes open, it takes 3 h to fill the tank. How long would it take to pipe C to empty it? \n" ); document.write( "
Algebra.Com's Answer #567345 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Pipe A's rate of filling is:
\n" ); document.write( "( 1 tank filled ) / ( 5 hrs )
\n" ); document.write( "------------------------
\n" ); document.write( "Let \"+t+\" = pipe C's time to
\n" ); document.write( "empty the tank, so C's rate
\n" ); document.write( "of emptying is:
\n" ); document.write( "( minus 1 tank filled ) / ( t hrs )
\n" ); document.write( "-----------------------------
\n" ); document.write( "Pipe B's rate of filling is:
\n" ); document.write( "( 1 tank filled ) / ( t - 2 hrs )
\n" ); document.write( "-------------------------
\n" ); document.write( "With all 3 pipes open, the rate of filling is:
\n" ); document.write( "( 1 tank filled ) / ( 3 hrs ), so I can say:
\n" ); document.write( "\"+1%2F5+%2B+1%2F%28+t-2+%29+-+1%2Ft+=+1%2F3+\"
\n" ); document.write( "Multiply both sides by:
\n" ); document.write( "\"+15%2At%2A%28+t-2+%29+\"
\n" ); document.write( "\"+3t%2A%28+t-2+%29+%2B+15t+-+15%2A%28+t-2+%29+=+5t%2A%28+t-2+%29+\"
\n" ); document.write( "\"+5t%2A%28+t-2+%29+-+3t%2A%28+t-2+%29+=+15t+-+15%2A%28+t-2+%29+\"
\n" ); document.write( "\"+2t%2A%28+t-2+%29+=+15t+-+15t+%2B+30+\"
\n" ); document.write( "\"+2t%5E2+-+4t+-+30+=+0+\"
\n" ); document.write( "\"+t%5E2+-+2t+-+15+=+0+\"
\n" ); document.write( "\"+%28+t+-+5+%29%2A%28+t+%2B+3+%29+=+0+\"
\n" ); document.write( "\"+t+=+5+\" ( can't use negative time )
\n" ); document.write( "Pipe C can empty the tank in 5 hrs
\n" ); document.write( "check:
\n" ); document.write( "\"+1%2F5+%2B+1%2F%28+t-2+%29+-+1%2Ft+=+1%2F3+\"
\n" ); document.write( "\"+1%2F5+%2B+1%2F%28+5-2+%29+-+1%2F5+=+1%2F3+\"
\n" ); document.write( "\"+1%2F5+%2B+1%2F3+-+1%2F5+=+1%2F3+\"
\n" ); document.write( "\"+1%2F3+=+1%2F3+\"
\n" ); document.write( "OK\r
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