document.write( "Question 934184: john has a total of 13 coins in his pocket. of the 13 coins they are all either quarters or dimes. the total value of the coins is $2.50. how many quarters does john have in his pocket?
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Algebra.Com's Answer #567305 by Edwin McCravy(20060)\"\" \"About 
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john has a total of 13 coins in his pocket. of the 13 coins they are all either
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document.write( "Let the number of nickels be x\r\n" );
document.write( "Then the number of dimes, using \r\n" );
document.write( "ONE PART = TOTAL MINUS OTHER PART,\r\n" );
document.write( "is 13-x.  \r\n" );
document.write( "                      Value      Value\r\n" );
document.write( "Type       Number       of         of\r\n" );
document.write( " of          of        EACH       ALL\r\n" );
document.write( "coin        coins      coin      coins\r\n" );
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document.write( "QUARTERS     x        $0.25    $0.25x \r\n" );
document.write( "DIMES      13-x       $0.10    $0.10(13-x)\r\n" );
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document.write( "TOTALS      13        -----    $2.50\r\n" );
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document.write( " The equation comes from the column on the right\r\n" );
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document.write( "  \"%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cquarters%29%29\"\"%22%22%2B%22%22\"\"%28matrix%284%2C1%2CValue%2Cof%2CALL%2Cdimes%29%29\"\"%22%22=%22%22\"\"%28matrix%285%2C1%2CTotal%2Cvalue%2Cof%2CALL%2Ccoins%29%29\"\r\n" );
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document.write( "0.25x + 0.10(13-x) = 2.50\r\n" );
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document.write( "Get rid of decimals by multiplying every term by 100\r\n" );
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document.write( "     25x + 10(13-x) = 250\r\n" );
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document.write( "    25x + 130 - 10x = 250\r\n" );
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document.write( "          15x + 130 = 250\r\n" );
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document.write( "                15x = 120\r\n" );
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document.write( "                  x = 8 = the number of quarters\r\n" );
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document.write( "The number of dimes is 13-x or 13-8 or 5 dimes.\r\n" );
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document.write( "Checking:  8 quarters is $2.00 and 5 dimes is $0.50\r\n" );
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document.write( "And indeed $2.00+$0.50 = $2.50.\r\n" );
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document.write( "Edwin
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