document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=934173>Question 934173</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%5E%283x%29=3%5E%282x%2B1%29 ALIGN=MIDDLE  ALT=\"2%5E%283x%29=3%5E%282x%2B1%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #567285 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=567285\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2^(3x)=3^(2x+1) <BR>\n" );
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document.write( "Take the log of both sides::<BR>\n" );
document.write( "(3x)log(2) = (2x+1)log(3)<BR>\n" );
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document.write( "(3x)/(2x+1) = log(3)/log(2)<BR>\n" );
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document.write( "3x/(2x+1) = 1.585<BR>\n" );
document.write( "---<BR>\n" );
document.write( "3x = 1.585(2x+1)<BR>\n" );
document.write( "3x = 3.17x + 1.585<BR>\n" );
document.write( "0.17x = -1.585<BR>\n" );
document.write( "x = -9.324<BR>\n" );
document.write( "---------------<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "--------------- </SPAN>\n" );
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