document.write( "Question 934165: Mike and Joe take 3 3/4 hrs to do a job. Joe alone takes 10 hrs to do the same job. How long would it take Mike to do the same job alone? \n" ); document.write( "
Algebra.Com's Answer #567273 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Mike and Joe take 3 3/4 hrs to do a job. Joe alone takes 10 hrs to do the same job. How long would it take Mike to do the same job alone? \n" ); document.write( "------------------ \n" ); document.write( "Together DATA:: time = 15/4 hr/job ; rate:: 4/15 job/hr \n" ); document.write( "Joe DATA:: time = 10 hr/job ; rate = 1/10 job/hr \n" ); document.write( "Mike DATA: time = x hr/job ; rate = 1/x job/hr \n" ); document.write( "----- \n" ); document.write( "Equation: \n" ); document.write( "rate + rate = together rate \n" ); document.write( "1/x + 1/10 = 4/15 \n" ); document.write( "--- \n" ); document.write( "150 + 15x = 40x \n" ); document.write( "---- \n" ); document.write( "25x = 150 \n" ); document.write( "x = 6 (time for Mike to do the job alone) \n" ); document.write( "---------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "-------------- \n" ); document.write( " |