document.write( "Question 79054: Ching leaves San Francisco and travels toward Los Angeles at 50 mi/h. An hour later, Phil leaves Los Angeles and travels toward San Francisco at 60 mi/h. If the two cities are 380 miles apart, how many hours will it take for Ching to meet Phil? \n" ); document.write( "
Algebra.Com's Answer #56725 by ptaylor(2198)![]() ![]() You can put this solution on YOUR website! Distance(d)equals rate(r) times time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "Let t=number of hours its takes for Ching to meet Phil after Phil leaves \n" ); document.write( "Then t+1=total number of hours it will take for Ching to meet Phil\r \n" ); document.write( "\n" ); document.write( "distance Ching travels=50t+50\r \n" ); document.write( "\n" ); document.write( "distance Phil travels=60t\r \n" ); document.write( "\n" ); document.write( "Now when the sum of the distances traveled by each equals 360 miles, then they will be together. So\r \n" ); document.write( "\n" ); document.write( "50t+50+60t=360 subtract 50 from both sides \n" ); document.write( "50t+50-50+60t=360-50 collect like terms\r \n" ); document.write( "\n" ); document.write( "110t=310 divide both sides by 110\r \n" ); document.write( "\n" ); document.write( "t=2.818 hours---hours it takes for Ching to meet Phil after Phil leaves \n" ); document.write( "t+1=2.818+1=3.818 hours --total hours it takes for Ching to meet Phil\r \n" ); document.write( "\n" ); document.write( "Check\r \n" ); document.write( "\n" ); document.write( "60*2.818+50*3.818=360\r \n" ); document.write( "\n" ); document.write( "169.08+190.9=360 \n" ); document.write( "~360=360\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |