document.write( "Question 934141: If you wish to increase the percent of acid in 60 mL of a 25% acid solution in water to 35% acid, how much pure acid must you add? \n" ); document.write( "
Algebra.Com's Answer #567245 by mananth(16946)\"\" \"About 
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--- percent ---------------- Quantity
\n" ); document.write( "Acid I 25 ---------------- 60 ml
\n" ); document.write( "Pure acid 100 ---------------- x ml
\n" ); document.write( "Mixture 35 ---------------- 60 + x ml
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\n" ); document.write( "25 * 60 + 100 x = 35 ( 60 + x )
\n" ); document.write( "1500 + 100 x = 2100 + 35 x
\n" ); document.write( "100 x -35 x = -1500 + 2100
\n" ); document.write( "65 x = 600
\n" ); document.write( "/ 65
\n" ); document.write( "x = 9.23 ml Pure acid
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\n" ); document.write( "m.ananth@hotmail.ca
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