document.write( "Question 934086: 52 inch tv cost 1,995 which was 5% less than the year before, how much was it the year before \n" ); document.write( "
Algebra.Com's Answer #567235 by Theo(13342)\"\" \"About 
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it was 1995 last year.
\n" ); document.write( "it's 5% less this year.\r
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\n" ); document.write( "\n" ); document.write( "let x = last year's price.
\n" ); document.write( "last year's price minus 5% of last year's price becomes x - .05 * x = 1995
\n" ); document.write( "factor out the x to get (1 - .05) * x = 1995
\n" ); document.write( "simplify to get .95 * x = 1995
\n" ); document.write( "solve for x to get x = 1995 / .95 = 2100.\r
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\n" ); document.write( "\n" ); document.write( "it was 2100 last year.
\n" ); document.write( "5% of 2100 = 105
\n" ); document.write( "subtract 105 from 2100 and you get 1995.\r
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\n" ); document.write( "\n" ); document.write( "your solution is that it was 2100 last year.\r
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