document.write( "Question 934100: Two cars leave town A at the same time and travel 480 miles (each) to town B. The speed of the slower car is 20 mph less than the speed of the faster one. If the slower car arrives at Town B two hours after the faster car, the what is the speed ( in mph) of the faster car? \n" ); document.write( "
Algebra.Com's Answer #567211 by mananth(16946)\"\" \"About 
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Car I speed x
\n" ); document.write( "Car II speed x + -20
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\n" ); document.write( " Distance = same 480 miles 1
\n" ); document.write( " Car II time - Car I time = 2 hours
\n" ); document.write( " t=d/t
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\n" ); document.write( " 480 / x - 480 / ( x + -20 ) = 2.00
\n" ); document.write( " LCD= x ( x + -20 )
\n" ); document.write( " multiply by LCD
\n" ); document.write( " 480 ( x + -20 ) - 480 x = 2 x ( x + -20 )
\n" ); document.write( " 480 x + -9600 - 480 x = 2 X^2 + -40 x
\n" ); document.write( " -9600 = 2 X^2 + -40 x
\n" ); document.write( " 2 X^2 -40 x - 9600 = 0
\n" ); document.write( "/2
\n" ); document.write( "x^2-20x-4800=0\r
\n" ); document.write( "\n" ); document.write( "x^2-20x+100= 4800+100\r
\n" ); document.write( "\n" ); document.write( "(x-10)^2= 4900\r
\n" ); document.write( "\n" ); document.write( "x-10 = 70 ( taking positive)\r
\n" ); document.write( "\n" ); document.write( "x= 80\r
\n" ); document.write( "\n" ); document.write( "Car I ------80 mph
\n" ); document.write( "Car II-------60 mph\r
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